The Peltier coefficient of a thermocouple is | vedclass

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(A) The heat $H$ developed at a junction due to the Peltier effect is given by the formula: $H = \pi I t$,where $\pi$ is the Peltier coefficient,$I$ i

Vedclass · Accepted Answer

$6 \, ergs$

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(A) The heat $H$ developed at a junction due to the Peltier effect is given by the formula: $H = \pi I t$,where $\pi$ is the Peltier coefficient,$I$ is the current,and $t$ is the time.Given: $\pi = 2 	imes 10^{-9} \, V$,$I = 2.5 \, A$,and $t = 2 \, min = 120 \, s$.Substituting the values: $H = (2 	imes 10^{-9}) 	imes 2.5 	imes 120 = 600 	imes 10^{-9} \, J = 6 	imes 10^{-7} \, J$.Since $1 \, J = 10^7 \, ergs$,we convert the heat into ergs: $H = (6 	imes 10^{-7} \, J) 	imes (10^7 \, ergs/J) = 6 \, ergs$.Therefore,the correct option is $A$.

The Peltier coefficient of a thermocouple is $2 \times 10^{-9} \, V$. How much heat is developed at a junction if a $2.5 \, A$ current flows for $2 \, min$?

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