Paschim Express left Delhi for Mumbai at 14:3 | vedclass

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(B) Let the two trains meet at a distance of $x\, 	ext{km}$ from Delhi.The time taken by Paschim Express to cover $x\, 	ext{km}$ is $t_1 = \frac{x}{

Vedclass · Accepted Answer

$480$

Vedclass · Answer

(B) Let the two trains meet at a distance of $x\, 	ext{km}$ from Delhi.The time taken by Paschim Express to cover $x\, 	ext{km}$ is $t_1 = \frac{x}{60}\, 	ext{hours}$.The time taken by August Kranti Express to cover $x\, 	ext{km}$ is $t_2 = \frac{x}{80}\, 	ext{hours}$.Since August Kranti Express starts $2\, 	ext{hours}$ later than Paschim Express $(16:30 - 14:30 = 2\, 	ext{hours})$,the difference in time taken is $2\, 	ext{hours}$.Therefore,$\frac{x}{60} - \frac{x}{80} = 2$.Taking the least common multiple of $60$ and $80$,which is $240$:$\frac{4x - 3x}{240} = 2$.$\frac{x}{240} = 2$.$x = 480\, 	ext{km}$.Thus,the two trains will meet at a distance of $480\, 	ext{km}$ from Delhi.

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