(A) Let the weight of one circle be $x$ and the weight of one square be $y$.From the first balance,we have $3$ circles on the left and $4$ squares on

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) Let the weight of one circle be $x$ and the weight of one square be $y$.From the first balance,we have $3$ circles on the left and $4$ squares on the right,which are in equilibrium. Therefore,$3x = 4y$.From the second balance,we have $1$ circle and $2$ squares on the left,and a weight of $10$ units on the right. Therefore,$x + 2y = 10$.Thus,the pair of equations is $3x = 4y$ and $x + 2y = 10$.

Class 10 Mathematics Pair of Linear Equations in Two Variables Mix Examples - Pair of Linear Equations in Two Variables

Difficult

The pair of equations represented by the above figures is:

A
$3x = 4y, x + 2y = 10$
B
$x = y, 2x + y = 10$
C
$2x = y, 2x + y = 10$
D
$x = 2y, x + 2y = 10$

Explore More

Browse All

Question Bank

All Subjects

Class 10 Questions

Class 10

Mathematics Questions

Chapter

Pair of Linear Equations in Two Variables

Subtopic

Mix Examples - Pair of Linear Equations in Two Variables

The present age of Ramesh is $x$ years. Mahesh is $5$ years elder than Ramesh and three years younger than Suresh. The present age of Suresh is $\ldots \ldots \ldots \ldots$

Medium

View Solution

Solve the following pair of equations by the method of cross multiplication:
$x + y - (a + b) = 0$
$ax - by - (a^2 - b^2) = 0$

Difficult

View Solution

Solve the following pairs of equations by the cross-multiplication method:
$x - 3y = -5$
$3x = 7y - 13$

Easy

View Solution

Solve the following pair of linear equations in two variables using a graph: $3x + 6y = 4$ and $2x + 4y = \frac{8}{3}$.

Medium

View Solution

From the pair of equations $x + 2y = 8 \dots(1)$ and $3x - 4y = -6 \dots(2)$,the first equation should be multiplied by ............. to eliminate $y$.

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The pair of equations represented by the above figures is:

Similar Questions

The present age of Ramesh is $x$ years. Mahesh is $5$ years elder than Ramesh and three years younger than Suresh. The present age of Suresh is $\ldots \ldots \ldots \ldots$

Solve the following pair of equations by the method of cross multiplication:$x + y - (a + b) = 0$$ax - by - (a^2 - b^2) = 0$

Solve the following pairs of equations by the cross-multiplication method:$x - 3y = -5$$3x = 7y - 13$

Solve the following pair of linear equations in two variables using a graph: $3x + 6y = 4$ and $2x + 4y = \frac{8}{3}$.

From the pair of equations $x + 2y = 8 \dots(1)$ and $3x - 4y = -6 \dots(2)$,the first equation should be multiplied by ............. to eliminate $y$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Solve the following pair of equations by the method of cross multiplication:
$x + y - (a + b) = 0$
$ax - by - (a^2 - b^2) = 0$

Solve the following pairs of equations by the cross-multiplication method:
$x - 3y = -5$
$3x = 7y - 13$