Ozonolysis of o-xylene produces: | vedclass

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Question

(C) $o$-Xylene exists in two resonance structures. Ozonolysis of these structures breaks the double bonds to form dicarbonyl compounds.Structure $I$ i

Vedclass · Accepted Answer

$I:II:III = 1:2:3$

Vedclass · Answer

(C) $o$-Xylene exists in two resonance structures. Ozonolysis of these structures breaks the double bonds to form dicarbonyl compounds.Structure $I$ is $CH_3-CO-CO-CH_3$ (butane$-2,3-$dione).Structure $II$ is $CH_3-CO-CHO$ ($2$-oxopropanal).Structure $III$ is $CHO-CHO$ (ethanedial).From the resonance structures of $o$-xylene,ozonolysis yields:$1$ mole of $I$ (butane$-2,3-$dione),$2$ moles of $II$ ($2$-oxopropanal),$3$ moles of $III$ (ethanedial).Therefore,the ratio of the products is $I:II:III = 1:2:3$.

Ozonolysis of $o$-xylene produces:

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