Oxygen is more electronegative than sulphur,yet $H_2S$ is acidic in nature while $H_2O$ is neutral. This is because:

  • A
    $H_2S$ molecules are associated due to inter-molecular $H$-bonding
  • B
    $H_2O$ has a higher boiling point than $H_2S$
  • C
    $H-S$ bond is weaker than $O-H$ bond
  • D
    $H_2S$ is a gas at ordinary temperature while $H_2O$ is a liquid

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Given below are two statements:
Statement $I$: The boiling point of hydrides of Group $16$ elements follows the order
$H_2O > H_2Te > H_2Se > H_2S$.
Statement $II$: On the basis of molecular mass,$H_2O$ is expected to have a lower boiling point than the other members of the group,but due to the presence of extensive $H$-bonding in $H_2O$,it has a higher boiling point.
In the light of the above statements,choose the correct answer from the options given below:

Why is dioxygen a gas but sulphur a solid?

Which of the following statements is $INCORRECT$?

$A$ pale yellow solid molecule $(A)$ having crown shape is heated with conc. $H_2SO_4$. It gives a suffocating smell of gas $(B)$,which when passed through starch iodate paper,turns it blue. The gas $(B)$ is:

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Which oxide is used as a catalyst in the contact process?

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