Oxidation state of S in H_2S_2O_8 is | vedclass

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(B) In the structure of $H_2S_2O_8$ (peroxodisulphuric acid),there is a peroxide linkage $(-O-O-)$. Two oxygen atoms are involved in the peroxide link

Vedclass · Accepted Answer

$6$

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(B) In the structure of $H_2S_2O_8$ (peroxodisulphuric acid),there is a peroxide linkage $(-O-O-)$. Two oxygen atoms are involved in the peroxide linkage,each having an oxidation state of $-1$. The remaining $6$ oxygen atoms have an oxidation state of $-2$. Let the oxidation state of $S$ be $x$. Applying the oxidation state rule: $2(+1) + 2(x) + 2(-1) + 6(-2) = 0$. $2 + 2x - 2 - 12 = 0$. $2x = 12$. $x = +6$.

Oxidation state of $S$ in $H_2S_2O_8$ is

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