Oxidation of allyl alcohol with a peracid giv | vedclass

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(C) The oxidation of allyl alcohol $(CH_2=CH-CH_2OH)$ with a peracid $(RCO_3H)$ is an epoxidation reaction.This reaction yields glycidol,which has the

Vedclass · Accepted Answer

$CH_2(O)CH-CH_2OH$ (glycidol)

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(C) The oxidation of allyl alcohol $(CH_2=CH-CH_2OH)$ with a peracid $(RCO_3H)$ is an epoxidation reaction.This reaction yields glycidol,which has the molecular formula $C_3H_6O_2$.The structure of glycidol is $CH_2(O)CH-CH_2OH$ (or $2,3-$epoxypropan$-1-$ol).In this molecule,the carbon atom at the $C-2$ position is bonded to four different groups ($-H$,$-CH_2OH$,and the two carbons of the epoxide ring),making it an asymmetric (chiral) carbon atom.Therefore,the correct structure is $CH_2(O)CH-CH_2OH$.

Oxidation of allyl alcohol with a peracid gives a compound of molecular formula $C_3H_6O_2$,which contains an asymmetric carbon atom. The structure of the compound is

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