(A) Let the oxidation number of $P$ be $x$. In $KH_2PO_2$,the oxidation numbers of $K$,$H$,and $O$ are $+1$,$+1$,and $-2$ respectively. The sum of oxi

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(A) Let the oxidation number of $P$ be $x$. In $KH_2PO_2$,the oxidation numbers of $K$,$H$,and $O$ are $+1$,$+1$,and $-2$ respectively. The sum of oxidation numbers of all atoms in a neutral molecule is $0$. Therefore,$(+1) + 2(+1) + x + 2(-2) = 0$. $1 + 2 + x - 4 = 0$. $3 + x - 4 = 0$. $x - 1 = 0$. $x = +1$.