(D) Let the oxidation number of $N$ be $x$. The oxidation number of $H$ is $+1$ and that of $O$ is $-2$. For the neutral molecule $HNO_3$,the sum of o

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(D) Let the oxidation number of $N$ be $x$. The oxidation number of $H$ is $+1$ and that of $O$ is $-2$. For the neutral molecule $HNO_3$,the sum of oxidation numbers is $0$. $(+1) + x + 3(-2) = 0$ $1 + x - 6 = 0$ $x - 5 = 0$ $x = +5$ Thus,the oxidation number of $N$ in $HNO_3$ is $+5$.