Oxalic acid reacts with concentrated H_2SO_4 | vedclass

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(C) When oxalic acid $(COOH)_2$ is heated with concentrated $H_2SO_4$,it undergoes dehydration to produce a mixture of carbon monoxide $(CO)$ and carb

Vedclass · Accepted Answer

$K_2CO_3$

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(C) When oxalic acid $(COOH)_2$ is heated with concentrated $H_2SO_4$,it undergoes dehydration to produce a mixture of carbon monoxide $(CO)$ and carbon dioxide $(CO_2)$ gases along with water: $(COOH)_2 \xrightarrow{conc. H_2SO_4} CO + CO_2 + H_2O$ When this gaseous mixture is passed through caustic potash $(KOH)$,the acidic gas $CO_2$ is absorbed,while $CO$ (a neutral gas) passes through. The reaction between $CO_2$ and $KOH$ is: $CO_2 + 2KOH \rightarrow K_2CO_3 + H_2O$ Thus,the product formed is potassium carbonate $(K_2CO_3)$.

Oxalic acid reacts with concentrated $H_2SO_4$ to give a mixture of two gases. When this mixture is passed through caustic potash,one of the gases is absorbed. What is the product formed by the absorbed gas with caustic potash?

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