Over the past $200$ working days,the number of defective parts produced by a machine is given in the following table:
Number of defective parts $0$ $1$ $2$ $3$ $4$ $5$ $6$ $7$ $8$ $9$ $10$ $11$ $12$ $13$ Days $50$ $32$ $22$ $18$ $12$ $12$ $10$ $10$ $10$ $8$ $6$ $6$ $2$ $2$
Determine the probability that tomorrow's output will have not more than $5$ defective parts.
| Number of defective parts | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ | $7$ | $8$ | $9$ | $10$ | $11$ | $12$ | $13$ |
| Days | $50$ | $32$ | $22$ | $18$ | $12$ | $12$ | $10$ | $10$ | $10$ | $8$ | $6$ | $6$ | $2$ | $2$ |
Determine the probability that tomorrow's output will have not more than $5$ defective parts.
- A$0.73$
- B$0.63$
- C$0.53$
- D$0.43$
Explore More
Similar Questions
Here is an extract from a mortality table.
Age (in years) Number of persons surviving out of a sample of one million $60$ $16090$ $61$ $11490$ $62$ $8012$ $63$ $5448$ $64$ $3607$ $65$ $2320$
What is the probability that a person aged $61$ will live for $4$ years?
| Age (in years) | Number of persons surviving out of a sample of one million |
| $60$ | $16090$ |
| $61$ | $11490$ |
| $62$ | $8012$ |
| $63$ | $5448$ |
| $64$ | $3607$ |
| $65$ | $2320$ |
What is the probability that a person aged $61$ will live for $4$ years?
Medium
View Solution$A$ recent survey found that the ages of workers in a factory is distributed as follows:
Age (in years) $20-29$ $30-39$ $40-49$ $50-59$ $60$ and above Number of workers $38$ $27$ $86$ $46$ $3$
If a person is selected at random,find the probability that the person is under $40$ years.
| Age (in years) | $20-29$ | $30-39$ | $40-49$ | $50-59$ | $60$ and above |
| Number of workers | $38$ | $27$ | $86$ | $46$ | $3$ |
If a person is selected at random,find the probability that the person is under $40$ years.
Medium
View Solution$50$ families with $2$ children were selected randomly and the following data were recorded:
Number of girls in a family $0$ $1$ $2$ Number of families $10$ $32$ $8$
If a family is chosen at random,compute the probability that it has: $(1)$ two girls,$(2)$ one girl,$(3)$ no girl.
| Number of girls in a family | $0$ | $1$ | $2$ |
| Number of families | $10$ | $32$ | $8$ |
If a family is chosen at random,compute the probability that it has: $(1)$ two girls,$(2)$ one girl,$(3)$ no girl.
Medium
View SolutionBulbs are packed in cartons,each containing $40$ bulbs. Seven hundred cartons were examined for defective bulbs,and the results are given in the following table:
Number of defective bulbs $0$ $1$ $2$ $3$ $4$ $5$ $6$ more than $6$ Frequency $400$ $180$ $48$ $41$ $18$ $8$ $3$ $2$
One carton was selected at random. What is the probability that it has less than $4$ defective bulbs?
| Number of defective bulbs | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ | more than $6$ |
| Frequency | $400$ | $180$ | $48$ | $41$ | $18$ | $8$ | $3$ | $2$ |
One carton was selected at random. What is the probability that it has less than $4$ defective bulbs?
Medium
View SolutionTwo dice are thrown simultaneously $500$ times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:
Sum Frequency $2$ $14$ $3$ $30$ $4$ $42$ $5$ $55$ $6$ $72$ $7$ $75$ $8$ $70$ $9$ $53$ $10$ $46$ $11$ $28$ $12$ $15$
If the dice are thrown once more,what is the probability of getting a sum $3\,?$
| Sum | Frequency |
| $2$ | $14$ |
| $3$ | $30$ |
| $4$ | $42$ |
| $5$ | $55$ |
| $6$ | $72$ |
| $7$ | $75$ |
| $8$ | $70$ |
| $9$ | $53$ |
| $10$ | $46$ |
| $11$ | $28$ |
| $12$ | $15$ |
If the dice are thrown once more,what is the probability of getting a sum $3\,?$
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo