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(A) The root mean square speed of a gas molecule is given by the formula $v_{	ext{rms}} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas consta

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Hydrogen

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(A) The root mean square speed of a gas molecule is given by the formula $v_{	ext{rms}} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas constant,$T$ is the absolute temperature,and $M$ is the molar mass of the gas.Since $v_{	ext{rms}} \propto \frac{1}{\sqrt{M}}$,the gas with the lower molar mass will have a higher $v_{	ext{rms}}$ at the same temperature.The molar mass of hydrogen $(H_2)$ is approximately $2 	ext{ g/mol}$,while the average molar mass of air is approximately $28.97 	ext{ g/mol}$.Since the molar mass of hydrogen is significantly lower than that of air,hydrogen will have a higher $v_{	ext{rms}}$.

Out of hydrogen and air,which will have a higher root mean square speed $(v_{\text{rms}})$?

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