The osmotic pressure of a 0.1 M solution of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The osmotic pressure $(\pi)$ is a colligative property given by the formula $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is the molar conce

Vedclass · Accepted Answer

Osmotic pressure of $Na_2SO_4$ solution will be more than $NaCl$ solution

Vedclass · Answer

(C) The osmotic pressure $(\pi)$ is a colligative property given by the formula $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is the molar concentration,$R$ is the gas constant,and $T$ is the temperature.For $NaCl$,it dissociates as $NaCl \rightarrow Na^+ + Cl^-$,so the van't Hoff factor $i = 2$.For $Na_2SO_4$,it dissociates as $Na_2SO_4 \rightarrow 2Na^+ + SO_4^{2-}$,so the van't Hoff factor $i = 3$.Since both solutions have the same molar concentration $(C = 0.1 \ M)$ and are at the same temperature,the osmotic pressure depends directly on the van't Hoff factor $i$.Because $i$ for $Na_2SO_4$ $(i=3)$ is greater than $i$ for $NaCl$ $(i=2)$,the osmotic pressure of the $Na_2SO_4$ solution will be higher.

The osmotic pressure of a $0.1 \ M$ solution of $NaCl$ and $Na_2SO_4$ will be:

Similar Questions

At a certain temperature,the vapour pressure of pure water is $76 \ mm$ of $Hg$. When $1 \ mol$ of $Na_2SO_4$ is dissolved in $36 \ mL$ of water,the vapour pressure of the solution becomes $38 \ mm$ of $Hg$. What is the percentage dissociation of $Na_2SO_4$ in the solution?

Which of the following salts has the same value of Van't Hoff factor $i$ as that of $K_4[Fe(CN)_6]$?

The freezing point depression of a $0.01 \ m$ aqueous solution of $[Pt(NH_3)_4Cl_4]$ is $0.0054^\circ C$. If $K_f$ for water is $1.80 \ K \ kg \ mol^{-1}$,what is the correct formula for the complex?

$A^{2+}$,$B^{2+}$ and $C^{-}$ form an ionic complex like $A_{x-2}[B(C)_x]_2$. If the complex is $75 \%$ dissociated in a solvent with $i=4$,the coordination number of $B$ is:

In an aqueous solution of $NaCl$,the mole fraction of the solvent is $0.9$. Then,the relative lowering in vapour pressure will be ......... $atm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module