Osmotic pressure is 0.0821 atm at a temperat | vedclass

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Question

(C) The formula for osmotic pressure is $\pi = CRT$,where $\pi$ is the osmotic pressure,$C$ is the concentration,$R$ is the gas constant $(0.0821 \ L

Vedclass · Accepted Answer

$0.33 	imes 10^{-2}$

Vedclass · Answer

(C) The formula for osmotic pressure is $\pi = CRT$,where $\pi$ is the osmotic pressure,$C$ is the concentration,$R$ is the gas constant $(0.0821 \ L \ atm \ K^{-1} \ mol^{-1})$,and $T$ is the temperature in Kelvin.Given: $\pi = 0.0821 \ atm$,$T = 300 \ K$,$R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$.Rearranging the formula for concentration: $C = \frac{\pi}{RT}$.Substituting the values: $C = \frac{0.0821}{0.0821 	imes 300} = \frac{1}{300} \ mol/L$.$C = 0.00333 \ mol/L = 0.33 	imes 10^{-2} \ mol/L$.

Osmotic pressure is $0.0821 \ atm$ at a temperature of $300 \ K$. Find the concentration in $mol/L$.

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