Determine the order of basic strength for the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The basic strength of aromatic amines depends on the availability of the lone pair on the nitrogen atom. Electron-withdrawing groups $(EWG)$ like

Vedclass · Accepted Answer

$Q < R < P$

Vedclass · Answer

(D) The basic strength of aromatic amines depends on the availability of the lone pair on the nitrogen atom. Electron-withdrawing groups $(EWG)$ like $-NO_2$ decrease basicity by pulling electron density away from the nitrogen atom through inductive and resonance effects. Electron-donating groups $(EDG)$ like $-CH_3$ (methyl) increase basicity.$P$: Contains one $-NO_2$ group and two $-CH_3$ groups. The $-CH_3$ groups are electron-donating,which increases the electron density on the nitrogen atom,making it the most basic among the three.$Q$: Contains three $-NO_2$ groups (two ortho,one para). These are strong electron-withdrawing groups that significantly reduce the electron density on the nitrogen atom,making it the least basic.$R$: Contains one $-NO_2$ group at the para position. It is less basic than $P$ (due to the absence of electron-donating groups) but more basic than $Q$ (which has three electron-withdrawing groups).Therefore,the order of basic strength is $Q < R < P$.

Determine the order of basic strength for the following compounds:

Similar Questions

The major product formed by the reaction of benzylamine with nitrous acid is

When chloroform reacts with ethyl amine in the presence of alcoholic $KOH$,the compound formed is

Which of the following compounds does not undergo the carbylamine reaction?

In the reaction $C_6H_5NH_2 + CHCl_3 + 3KOH \rightarrow A + 3KCl + 3H_2O$,what is '$A$'?

Identify the $CORRECT$ decreasing order of solubilities of alcohols,alkanes,and amines in water having comparable molar mass.

Vedclass Test Series

Exam Paper Generator

Online Exam Module