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(C) The basic strength of a species is inversely proportional to the stability of its conjugate acid.$(I)$ Conjugate acid is $CH_3COOH$ $(pK_a \approx

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$II > III > IV > I$

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(C) The basic strength of a species is inversely proportional to the stability of its conjugate acid.$(I)$ Conjugate acid is $CH_3COOH$ $(pK_a \approx 4.75)$$(II)$ Conjugate acid is $CH_3CH_3$ $(pK_a \approx 50)$$(III)$ Conjugate acid is $NH_3$ $(pK_a \approx 38)$$(IV)$ Conjugate acid is $C_6H_5OH$ $(pK_a \approx 10)$Since the order of acidic strength is $CH_3COOH > C_6H_5OH > NH_3 > CH_3CH_3$,the order of basic strength is the reverse: $CH_3CH_2^- > NH_2^- > C_6H_5O^- > CH_3COO^-$.Thus,the correct order is $(II) > (III) > (IV) > (I)$.

Determine the order of basic strength for the following compounds:
$(I)$ $CH_3COO^-$
$(II)$ $CH_3CH_2^-$
$(III)$ $NH_2^-$
$(IV)$ $C_6H_5O^-$

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Determine the order of basic strength for the following compounds:$(I)$ $CH_3COO^-$$(II)$ $CH_3CH_2^-$$(III)$ $NH_2^-$$(IV)$ $C_6H_5O^-$