Orange light of wavelength 6000 times 10^{-10 | vedclass

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(A) The condition for diffraction minima in a single slit experiment is given by $d \sin 	heta = n \lambda$,where $n = \pm 1, \pm 2, \pm 3, \dots$Sin

Vedclass · Accepted Answer

$198$

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(A) The condition for diffraction minima in a single slit experiment is given by $d \sin 	heta = n \lambda$,where $n = \pm 1, \pm 2, \pm 3, \dots$Since $|\sin 	heta| Given $d = 0.6 	imes 10^{-4} \ m = 6 	imes 10^{-5} \ m$ and $\lambda = 6000 	imes 10^{-10} \ m = 6 	imes 10^{-7} \ m$.Calculating the ratio: $\frac{d}{\lambda} = \frac{6 	imes 10^{-5}}{6 	imes 10^{-7}} = 100$.Thus,$n Therefore,the number of minima on one side is $99$.The total number of minima on both sides of the central maximum is $99 + 99 = 198$.

Orange light of wavelength $6000 \times 10^{-10} \ m$ illuminates a single slit of width $0.6 \times 10^{-4} \ m$. The maximum possible number of diffraction minima produced on both sides of the central maximum is $........$

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