Optical isomerism arises due to the presence of

  • A
    An asymmetric carbon atom
  • B
    Centre of symmetry
  • C
    Axis of symmetry
  • D
    Plane of symmetry

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Which of the following is optically active?

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The compound$(s)$ showing optical activity is/are:

Which of the following is an optically active molecule?

The Fischer projection of $D$-erythrose is shown below.
$D$-Erythrose and its isomers are listed as $P$,$Q$,$R$,and $S$ in Column-$I$. Choose the correct relationship of $P$,$Q$,$R$,and $S$ with $D$-erythrose from Column-$II$.
Column-$I$:
$P$: $CHO-C(OH)(H)-C(OH)(H)-CH_2OH$ (rotated)
$Q$: $CHO-C(H)(OH)-C(OH)(H)-CH_2OH$
$R$: $CHO-C(OH)(H)-C(H)(OH)-CH_2OH$
$S$: $CHO-C(H)(OH)-C(H)(OH)-CH_2OH$ (enantiomer)
Column-$II$:
$1$. Diastereomer
$2$. Identical
$3$. Enantiomer

The absolute configurations of the following compounds are respectively:

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