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(B) The total number of tickets in the bag is $40$,so the total number of possible outcomes is $40$.The tickets numbered from $1$ to $40$ that are mul

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$\frac{1}{5}$

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(B) The total number of tickets in the bag is $40$,so the total number of possible outcomes is $40$.The tickets numbered from $1$ to $40$ that are multiples of $5$ are: $5, 10, 15, 20, 25, 30, 35, 40$.Counting these,we find there are $8$ such tickets.Therefore,the number of favorable outcomes is $8$.The probability of an event is given by the formula: $P(E) = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of possible outcomes}}$.Substituting the values,we get: $P(E) = \frac{8}{40} = \frac{1}{5}$.

One ticket is drawn at random from a bag containing tickets numbered $1$ to $40$. The probability that the selected ticket has a number which is a multiple of $5$ is

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