One third litre of x M K_2Cr_2O_7 is requir | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The balanced chemical equation for the reaction is: $Cr_2O_7^{2-} + 6Fe^{2+} + 14H^+ \longrightarrow 2Cr^{3+} + 6Fe^{3+} + 7H_2O$ Moles of ferrous

Vedclass · Accepted Answer

$0.1$

Vedclass · Answer

(B) The balanced chemical equation for the reaction is: $Cr_2O_7^{2-} + 6Fe^{2+} + 14H^+ \longrightarrow 2Cr^{3+} + 6Fe^{3+} + 7H_2O$ Moles of ferrous ammonium sulphate $= M 	imes V = 0.1 \ M 	imes 2 \ L = 0.2 \ mol$. From the stoichiometry,$1 \ mole$ of $K_2Cr_2O_7$ reacts with $6 \ moles$ of $Fe^{2+}$. Moles of $K_2Cr_2O_7$ required $= \frac{0.2}{6} = \frac{0.1}{3} \ mol$. Molarity $x = \frac{n}{V} = \frac{0.1/3 \ mol}{1/3 \ L} = 0.1 \ M$. Thus,option $(B)$ is correct.

One third litre of $x \ M \ K_2Cr_2O_7$ is required to completely oxidise $2 \ L$ of $0.1 \ M$ ferrous ammonium sulphate in acidic medium. What is $x$?

Similar Questions

What is the normality of $1.5 \ M \ H_3PO_4$ (in $.5$)?

If the concentration of compound $AB_5$ is $10^{-3} \text{ mol/L}$,then the concentration of $B^{-}$ will be .......

Concentrated $HCl$ is $10 \, N$. How much volume of concentrated $HCl$ is required to prepare $1000 \, mL$ of $1 \, N$ $HCl$ by dilution?

At $STP$,the decomposition of $1 \, g$ of $CaCO_3$ will produce ........... liters of $CO_2$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module