One side of a square is increased by 30 %. To | vedclass

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(A) Let the side of the square be $x$.Initially,the area of the square is $A = x^2$.After increasing one side by $30 \%$,the new length is $x + 0.3x =

Vedclass · Accepted Answer

$23 \frac{1}{13} \%$

Vedclass · Answer

(A) Let the side of the square be $x$.Initially,the area of the square is $A = x^2$.After increasing one side by $30 \%$,the new length is $x + 0.3x = 1.3x$.Let the other side be $y$ such that the area remains $x^2$.So,$1.3x 	imes y = x^2$.$y = \frac{x^2}{1.3x} = \frac{x}{1.3} = \frac{10x}{13}$.The decrease in the other side is $x - \frac{10x}{13} = \frac{3x}{13}$.The percentage decrease is $\left( \frac{3x/13}{x} ight) 	imes 100 = \frac{300}{13} \% = 23 \frac{1}{13} \%$.

One side of a square is increased by $30 \%$. To maintain the same area,the other side will have to be decreased by:

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