(B) For an adiabatic process,the work done is given by the change in internal energy: $W = \Delta U = nC_v(T_2 - T_1)$.Given: $n = 1\, mol$,$C_v = 20\

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(B) For an adiabatic process,the work done is given by the change in internal energy: $W = \Delta U = nC_v(T_2 - T_1)$.Given: $n = 1\, mol$,$C_v = 20\, J/K$,$T_1 = 27 + 273 = 300\, K$,and $W = -3000\, J$ (work done by the system is negative).Substituting the values: $-3000 = 1 \times 20 \times (T_2 - 300)$.$-150 = T_2 - 300$.$T_2 = 300 - 150 = 150\, K$.

Class 11 Chemistry Thermodynamics First law of thermodynamics

Medium

One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of $27\,^{\circ}C$. If the work done during the process is $3\, kJ$,then the final temperature of the gas is $(C_v = 20\, J/K)$ .....$K$

A
$100$
B
$150$
C
$195$
D
$255$

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First law of thermodynamics

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One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of $27\,^{\circ}C$. If the work done during the process is $3\, kJ$,then the final temperature of the gas is $(C_v = 20\, J/K)$ .....$K$

Similar Questions

“The mass and energy both are conserved in an isolated system”,is the statement of

If $Q$ is the heat liberated from the system and $W$ is the work done on the system,then the first law of thermodynamics can be written as:

$A$ cup of water at $5^{\circ}C$ (system) is placed in a microwave oven and the oven is turned on for one minute,during which the water begins to boil. Which of the following options is true?

$A$ sample of liquid in a thermally insulated container (a calorimeter) is stirred for $2 \ hr$ by a mechanical linkage to a motor in the surroundings. For this process:

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