A cup of water at 5^{circ}C (system) is place | vedclass

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(B) The process involves heating water from $5^{\circ}C$ to $100^{\circ}C$ and then converting it into steam: $H_2O(\ell)_{5^{\circ}C} \longrightarrow

Vedclass · Accepted Answer

$q = +ve, w = -ve, \Delta U = +ve$

Vedclass · Answer

(B) The process involves heating water from $5^{\circ}C$ to $100^{\circ}C$ and then converting it into steam: $H_2O(\ell)_{5^{\circ}C} \longrightarrow H_2O(\ell)_{100^{\circ}C} \rightleftharpoons H_2O(g)_{100^{\circ}C}$.Since heat is absorbed by the system from the microwave,$q = +ve$.As the water expands during boiling against the external pressure,the system does work on the surroundings,so $w = -ve$.The internal energy of the system increases because the temperature rises and the phase changes from liquid to gas,which has higher potential energy,thus $\Delta U = +ve$.

$A$ cup of water at $5^{\circ}C$ (system) is placed in a microwave oven and the oven is turned on for one minute,during which the water begins to boil. Which of the following options is true?

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