One microgram of matter converted into energy will give:

Given below are two statements:
Statement $I$: For all elements,greater the mass of the nucleus,greater is the binding energy per nucleon.
Statement $II$: For all elements,nuclei with less binding energy per nucleon transform to nuclei with greater binding energy per nucleon.
In the light of the above statements,choose the correct answer from the options given below:

The deuteron is bound by nuclear forces just as the $H$-atom is made up of a proton and an electron bound by electrostatic forces. If we consider the force between the neutron and proton in a deuteron as given in the form of a Coulomb potential but with an effective charge $e'$: $F = \frac{1}{4\pi \epsilon_0} \frac{e'^2}{r^2}$,estimate the value of $(e'/e)$ given that the binding energy of a deuteron is $2.2 \text{ MeV}$.

The binding energy per nucleon for $_8O^{16}$ and $_8O^{17}$ are $7.97 \, MeV$ and $7.75 \, MeV$ respectively. The energy required to remove a neutron from $_8O^{17}$ is (in $MeV$):

The binding energy of nucleons in a nucleus can be affected by the pairwise Coulomb repulsion. Assume that all nucleons are uniformly distributed inside the nucleus. Let the binding energy of a proton be $E_b^p$ and the binding energy of a neutron be $E_b^n$ in the nucleus. Which of the following statement(s) is(are) correct?
$(A)$ $E_b^p - E_b^n$ is proportional to $Z(Z-1)$ where $Z$ is the atomic number of the nucleus.
$(B)$ $E_b^p - E_b^n$ is proportional to $A^{-1/3}$ where $A$ is the mass number of the nucleus.
$(C)$ $E_b^p - E_b^n$ is positive.
$(D)$ $E_b^p$ increases if the nucleus undergoes a beta decay emitting a positron.

The curve of binding energy per nucleon as a function of atomic mass number has a sharp peak for the helium nucleus. This implies that helium