One end of a uniform wire of length L and wei | vedclass

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(C) The stress at any point in the wire is defined as the force acting on the cross-section at that point divided by the area of cross-section $S$.At

Vedclass · Accepted Answer

$\frac{W_1 + (3W/4)}{S}$

Vedclass · Answer

(C) The stress at any point in the wire is defined as the force acting on the cross-section at that point divided by the area of cross-section $S$.At a height $3L/4$ from the lower end,the total force acting on the cross-section is the sum of the weight $W_1$ suspended at the bottom and the weight of the portion of the wire below that point.Since the wire is uniform,the weight of a portion of the wire is proportional to its length.The length of the wire below the point at height $3L/4$ from the lower end is $3L/4$.Therefore,the weight of this portion of the wire is $(3/4)W$.The total force at this cross-section is $F = W_1 + (3W/4)$.Thus,the stress is $\sigma = \frac{F}{S} = \frac{W_1 + (3W/4)}{S}$.

One end of a uniform wire of length $L$ and weight $W$ is attached rigidly to a point in the roof,and a weight $W_1$ is suspended from its lower end. If $S$ is the area of cross-section of the wire,the stress in the wire at a height $3L/4$ from its lower end is

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