One end of a thermally insulated rod is kept at a temperature $T_1$ and the other at $T_2$. The rod is composed of two sections of lengths $l_1$ and $l_2$ and thermal conductivities $K_1$ and $K_2$ respectively. The temperature at the interface of the two sections is
$\left( {{K_2}{l_2}{T_1} + {K_1}{l_1}{T_2}} \right)/\left( {{K_1}{l_1} + {K_2}{l_2}} \right)$
$\left( {{K_2}{l_1}{T_1} + {K_1}{l_2}{T_2}} \right)/\left( {{K_2}{l_1} + {K_1}{l_2}} \right)$
$\left( {{K_1}{l_2}{T_1} + {K_2}{l_1}{T_2}} \right)/\left( {{K_1}{l_2} + {K_2}{l_1}} \right)$
$\left( {{K_1}{l_1}{T_1} + {K_2}{l_2}{T_2}} \right)/\left( {{K_1}{l_1} + {K_2}{l_2}} \right)$
When thermal conductivity is said to be constant ?
Two identical rods of copper and iron are coated with wax uniformly. When one end of each is kept at temperature of boiling water, the length upto which wax melts are $8.4cm$ and $4.2cm$ respectively. If thermal conductivity of copper is $0.92$ , then thermal conductivity of iron is
The ratio of thermal conductivity of two rods of different material is $5 : 4$ . The two rods of same area of cross-section and same thermal resistance will have the lengths in the ratio
A constant potential difference is applied to the ends of a graphite rod, whose resistance decreases with a rise of temperature. The rod can be $(1)$ covered with asbestos or $(2)$ left open to atmosphere. Answer for steady state.
Consider two rods of same length and different specific heats $\left(S_{1}, S_{2}\right)$, conductivities $\left(K_{1}, K_{2}\right)$ and area of cross-sections $\left(A_{1}, A_{2}\right)$ and both having temperatures $T_{1}$ and $T_{2}$ at their ends. If rate of loss of heat due to conduction is equal, then