One card is drawn from a well shuffled deck of $52$ cards. If each outcome is equally likely, calculate the probability that the card will be a diamond not an ace
When a card is drawn from a well shuffled deck of $52$ cards, the number of possible outcomes is $52$
We assume that the event 'Card drawn is an ace' is $B.$
Therefore Card drawn is not an ace' should be $B ^{\prime}$
We know that $P \left( B ^{\prime}\right)=1- P ( B )=1-\frac{4}{52}=1-\frac{1}{13}=\frac{12}{13}$
A bag $x$ contains $3$ white balls and $2$ black balls and another bag $y$ contains $2$ white balls and $4$ black balls. A bag and a ball out of it are picked at random. The probability that the ball is white, is
The two events $A$ and $B$ have probabilities $0.25$ and $0.50$ respectively. The probability that both $A$ and $B$ occur simultaneously is $0.14$. Then the probability that neither $A$ nor $B$ occurs is
A bag contains $4$ white, $5$ black and $6$ red balls. If a ball is drawn at random, then what is the probability that the drawn ball is either white or red
A fair coin is tossed repeatedly. If tail appears on first four tosses then the probability of head appearing on fifth toss equals
Two dice are thrown. The events $A, B$ and $C$ are as follows:
$A:$ getting an even number on the first die.
$B:$ getting an odd number on the first die.
$C:$ getting the sum of the numbers on the dice $\leq 5$
Describe the events $B$ and $C$