(A) The standard atmospheric pressure is defined as $1 \ atm = 1.01325 \times 10^5 \ Pa$. Since $1 \ Pa = 10 \ dynes \ cm^{-2}$,we have $1 \ atm = 1.0

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(A) The standard atmospheric pressure is defined as $1 \ atm = 1.01325 \times 10^5 \ Pa$. Since $1 \ Pa = 10 \ dynes \ cm^{-2}$,we have $1 \ atm = 1.01325 \times 10^5 \times 10 \ dynes \ cm^{-2} = 1.01325 \times 10^6 \ dynes \ cm^{-2}$. Therefore,$1 \ atm$ is approximately equal to $10^6 \ dynes \ cm^{-2}$.