On what sum will the compound interest (in ₹) | vedclass

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(C) The formula for the amount $A$ with compound interest for a fractional time period $n = a \frac{b}{c}$ is given by $A = P(1 + \frac{R}{100})^a (1

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$5000$

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(C) The formula for the amount $A$ with compound interest for a fractional time period $n = a \frac{b}{c}$ is given by $A = P(1 + \frac{R}{100})^a (1 + \frac{\frac{b}{c} 	imes R}{100})$.Here,$A = P + CI$. Since the interest is ₹ $6352.50$,the total amount $A = P + 6352.50$.Substituting the values: $P + 6352.50 = P(1 + \frac{10}{100})^2 (1 + \frac{0.5 	imes 10}{100})$.$P + 6352.50 = P(1.1)^2 (1.05)$.$P + 6352.50 = P(1.21)(1.05)$.$P + 6352.50 = 1.2705P$.$6352.50 = 1.2705P - P$.$6352.50 = 0.2705P$.$P = \frac{6352.50}{0.2705} = 23484.28$ (This suggests the question implies the total amount is ₹ $6352.50$ rather than the interest).If we assume the total amount $A = 6352.50$:$6352.50 = P(1 + \frac{10}{100})^2 (1 + \frac{5}{100})$.$6352.50 = P(1.21)(1.05) = 1.2705P$.$P = \frac{6352.50}{1.2705} = 5000$.Thus,the principal sum is ₹ $5000$.

On what sum will the compound interest (in ₹) for $2 \frac{1}{2}$ years at $10 \%$ per annum amount to ₹ $6352.50$?

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