On what date of August, 1988 did Friday fall? | vedclass

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(A) To find the days in $August, 1988$,we first determine the day of the week for $August 1, 1988$.$1987$ years = $1600$ years + $300$ years + $87$ ye

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$5$

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(A) To find the days in $August, 1988$,we first determine the day of the week for $August 1, 1988$.$1987$ years = $1600$ years + $300$ years + $87$ years.Odd days in $1600$ years = $0$.Odd days in $300$ years = $1$.In $87$ years,there are $21$ leap years and $66$ ordinary years.Number of odd days = $(21 	imes 2) + (66 	imes 1) = 42 + 66 = 108$ days.$108 \div 7 = 15$ weeks and $3$ odd days.Now,calculate odd days from $January 1, 1988$ to $August 1, 1988$:$January(31) + February(29) + March(31) + April(30) + May(31) + June(30) + July(31) + August(1) = 214$ days.$214 \div 7 = 30$ weeks and $4$ odd days.Total odd days = $0 + 1 + 3 + 4 = 8$ days,which is $1$ odd day.Since $1$ odd day corresponds to Monday,$August 1, 1988$ was a Monday.If $August 1$ is Monday,then $August 2$ is Tuesday,$August 3$ is Wednesday,$August 4$ is Thursday,and $August 5$ is Friday.Therefore,Fridays in $August 1988$ fall on $5, 12, 19,$ and $26$.

On what date of $August, 1988$ did Friday fall?

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