On treating a mixture of two alkyl halides wi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction described is the Wurtz reaction,where alkyl halides react with $Na$ metal in dry ether to form alkanes.To obtain $2-$methylpropane $(

Vedclass · Accepted Answer

$2-$chloropropane and chloromethane

Vedclass · Answer

(A) The reaction described is the Wurtz reaction,where alkyl halides react with $Na$ metal in dry ether to form alkanes.To obtain $2-$methylpropane $(CH_3-CH(CH_3)-CH_3)$,the alkyl groups involved must be an isopropyl group $(CH_3-CH(CH_3)-)$ and a methyl group $(-CH_3)$.Therefore,the reactants are $2-$chloropropane $(CH_3-CH(Cl)-CH_3)$ and chloromethane $(CH_3Cl)$.The reaction is: $CH_3-CH(Cl)-CH_3 + CH_3Cl + 2Na \xrightarrow{	ext{dry ether}} CH_3-CH(CH_3)-CH_3 + 2NaCl$.

On treating a mixture of two alkyl halides with sodium metal in dry ether,$2-$methylpropane was obtained. The alkyl halides are

Similar Questions

Identify the straight-chain hydrocarbon that is an isomer of $3-$ethyl$-2-$methylhexane.

What is the chlorination of methane in the presence of $hv$?

Which of the following has the highest octane number?

When a certain alkane is mixed with chlorine and irradiated with ultraviolet light,only one monochloroalkane is formed. This alkane is likely to be:

An unknown compound $X$ on chlorination followed by Wurtz reaction and dehydrohalogenation gives ethene. Provide the complete reaction sequence in a stepwise manner.

Vedclass Test Series

Exam Paper Generator

Online Exam Module