On the addition of a solution containing CrO_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The solubility product $(K_{sp})$ values for the chromates of alkaline earth metals are in the order: $K_{sp}(CaCrO_4) > K_{sp}(SrCrO_4) > K_{sp}(

Vedclass · Accepted Answer

$BaCrO_4$

Vedclass · Answer

(C) The solubility product $(K_{sp})$ values for the chromates of alkaline earth metals are in the order: $K_{sp}(CaCrO_4) > K_{sp}(SrCrO_4) > K_{sp}(BaCrO_4)$.Since $BaCrO_4$ has the lowest $K_{sp}$ value,it requires the lowest concentration of $CrO_4^{2-}$ ions to exceed its solubility product.Therefore,$BaCrO_4$ will precipitate first upon the addition of $CrO_4^{2-}$ ions to the solution containing these cations.The reaction is: $Ba^{2+}(aq) + CrO_4^{2-}(aq) 	o BaCrO_4(s) \downarrow$ (Yellow precipitate).

On the addition of a solution containing $CrO_4^{2-}$ ions to a solution containing $Ba^{2+}$,$Sr^{2+}$,and $Ca^{2+}$ ions,the precipitate obtained first will be of

Similar Questions

$K_{sp}$ for $Cr(OH)_3$ is $2.7 \times 10^{-31}$. What is its solubility in moles / litre?

If the solubility product of $AB_2$ is $4 \times 10^{-12}$,then its solubility is .......?

The solubility of $A_2 X_3$ is '$y$' $M$. Its solubility product is:

Which of the following compounds does not dissolve in ammonium hydroxide solution?

Which of the following sulphides has the lowest solubility product?

Vedclass Test Series

Exam Paper Generator

Online Exam Module