On passing $H_2S$ gas through a solution of $Cu^{2+}$ and $Zn^{2+}$ ions,$CuS$ is precipitated first because

  • A
    Solubility product of $CuS$ is equal to the ionic product of $ZnS$
  • B
    Solubility product of $CuS$ is equal to the solubility product of $ZnS$
  • C
    Solubility product of $CuS$ is lower than the solubility product of $ZnS$
  • D
    Solubility product of $CuS$ is greater than the solubility product of $ZnS$

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