On mixing urea,the boiling point of $H_{2}O$ changed to $100.5^{\circ}C$. Calculate the freezing point of the solution,if $K_{f}$ of water is $1.87 \ K \cdot kg \cdot mol^{-1}$ and $K_{b}$ of water is $0.52 \ K \cdot kg \cdot mol^{-1}$. (in $^{\circ}C$)

  • A
    $-1$
  • B
    $-0.5$
  • C
    $-1.8$
  • D
    $0$

Explore More

Similar Questions

The freezing point of an aqueous solution is $-0.186 \ ^oC$. The boiling point of the same solution is ........ $^oC$. (Given: $K_f = 1.86 \ K \ kg \ mol^{-1}$ and $K_b = 0.512 \ K \ kg \ mol^{-1}$)

The osmotic pressure of a $0.5 \ M$ aqueous solution of $CH_3COOH$ having a $pH$ of $2$ at temperature $T$ is . . . . . . . (in $RT$)

$1.24 \ g$ of $AX_2$ (molar mass $124 \ g \ mol^{-1}$) is dissolved in $1 \ kg$ of water to form a solution with a boiling point of $100.0156^{\circ} C$,while $25.4 \ g$ of $AY_2$ (molar mass $250 \ g \ mol^{-1}$) in $2 \ kg$ of water constitutes a solution with a boiling point of $100.0260^{\circ} C$. $K_{b}(H_2O) = 0.52 \ K \ kg \ mol^{-1}$. Which of the following is correct?

An aqueous solution of a non-volatile solute boils at $100.15\,^{\circ}C$. If the solution is diluted with an equal volume of water,the freezing point of the resulting solution will be ...... $^{\circ}C$. (Given: $K_b = 0.512\,K\,kg\,mol^{-1}$ and $K_f = 1.86\,K\,kg\,mol^{-1}$ for water)

The freezing point of an aqueous solution is $-0.186^oC$. If the molal elevation constant and molal depression constant of the solvent are $0.512$ and $1.86$ respectively,then the elevation in boiling point is .......... $^oC$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo