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Question

(a) Energy $U = \frac{1}{2}\frac{{{Q^2}}}{C}$ for a charged capacitor charge $Q$ is constant and with the increase in separation $C$ will decrease $\l

Vedclass · Accepted Answer

Increases

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(a) Energy $U = \frac{1}{2}\frac{{{Q^2}}}{C}$ for a charged capacitor charge $Q$ is constant and with the increase in separation $C$ will decrease $\left( {C \propto \frac{1}{d}} \right)$, So overall $U$ will increase.

On increasing the plate separation of a charged condenser, the energy

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