On heating,lead(II) nitrate gives a brown gas | vedclass

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Question

(D) Lead$(II)$ nitrate decomposes on heating to give nitrogen dioxide $(NO_2)$,which is a brown gas $(A)$.$2Pb(NO_3)_2 \xrightarrow{\Delta} 2PbO + 4NO

Vedclass · Accepted Answer

$+3$

Vedclass · Answer

(D) Lead$(II)$ nitrate decomposes on heating to give nitrogen dioxide $(NO_2)$,which is a brown gas $(A)$.$2Pb(NO_3)_2 \xrightarrow{\Delta} 2PbO + 4NO_2 + O_2$On cooling,$NO_2$ dimerizes to form dinitrogen tetroxide $(N_2O_4)$,which is a colourless solid/liquid $(B)$.$2NO_2 \xrightarrow{	ext{cooling}} N_2O_4$$N_2O_4$ reacts with nitric oxide $(NO)$ to form dinitrogen trioxide $(N_2O_3)$,which is a blue solid $(C)$.$N_2O_4 + 2NO ightarrow 2N_2O_3$In $N_2O_3$,let the oxidation state of $N$ be $x$.$2(x) + 3(-2) = 0$ $\Rightarrow 2x - 6 = 0$ $\Rightarrow x = +3$.

On heating,lead$(II)$ nitrate gives a brown gas $(A).$ The gas $(A)$ on cooling changes to a colourless solid/liquid $(B).$ $(B)$ on heating with $NO$ changes to a blue solid $(C).$ The oxidation number of nitrogen in solid $(C)$ is :

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