On electrolysis,which of the following does n | vedclass

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(D) In the electrolysis of dilute $H_2SO_4$ using $Pt$ electrodes,$O_2$ is evolved at the anode due to the oxidation of water.However,when using $Cu$

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Dilute $H_2SO_4$ using $Cu$ electrode

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(D) In the electrolysis of dilute $H_2SO_4$ using $Pt$ electrodes,$O_2$ is evolved at the anode due to the oxidation of water.However,when using $Cu$ electrodes,the anode itself is active and undergoes oxidation instead of water.At the anode: $Cu(s) \rightarrow Cu^{2+}(aq) + 2e^-$At the cathode: $2H^+(aq) + 2e^- \rightarrow H_2(g)$Since $Cu$ is oxidized at the anode,oxygen gas is not liberated.

On electrolysis,which of the following does not give out oxygen?

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