On dissolving a moderate amount of sodium met | vedclass

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(D) When sodium metal dissolves in liquid $NH_3$,it undergoes the following reaction: $Na + (x+y)NH_3 \rightarrow [Na(NH_3)_x]^+ + [e(NH_3)_y]^-$. The

Vedclass · Accepted Answer

Liquid ammonia remains diamagnetic

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(D) When sodium metal dissolves in liquid $NH_3$,it undergoes the following reaction: $Na + (x+y)NH_3 \rightarrow [Na(NH_3)_x]^+ + [e(NH_3)_y]^-$. The ammoniated electrons $[e(NH_3)_y]^-$ are responsible for the blue color,high electrical conductivity,and paramagnetic nature of the solution. Therefore,the solution becomes paramagnetic,not diamagnetic. Thus,option $D$ is the correct answer.

On dissolving a moderate amount of sodium metal in liquid $NH_3$ at low temperature,which one of the following does not occur?

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