On catalytic reduction (H_2 / Pt),how many al | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The catalytic reduction of an alkene with $H_2 / Pt$ involves the addition of hydrogen across the double bond to form the corresponding alkane.To

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) The catalytic reduction of an alkene with $H_2 / Pt$ involves the addition of hydrogen across the double bond to form the corresponding alkane.To obtain $n$-butane $(CH_3-CH_2-CH_2-CH_3)$,the starting alkene must have a four-carbon straight chain.The possible alkenes with a four-carbon straight chain are:$1$. $1$-butene $(CH_2=CH-CH_2-CH_3)$$2$. $cis$-$2$-butene $(CH_3-CH=CH-CH_3)$$3$. $trans$-$2$-butene $(CH_3-CH=CH-CH_3)$All three of these alkenes,upon hydrogenation,yield $n$-butane.Therefore,there are $3$ such alkenes.

On catalytic reduction $(H_2 / Pt)$,how many alkenes will give $n$-butane?

Similar Questions

The major product of the following reaction is $CH_3-CH(Br)-CH_2-CH_3 + \text{alc. } KOH \to $

The major product of the following reaction is

The product $(C)$ is:

State Markovnikov's rule and explain it with an example.

$But-1-ene \xrightarrow[(ii) NaBH_4]{(i) (CH_3COO)_2Hg/H_2O} ?$
The product in the above reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module