On analysis,a saturated hydrocarbon is found | vedclass

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Question

(C) To find the empirical formula,we calculate the mole ratio of the elements present:

	
		
			Element
			Moles $(	ext{mass}/	ext{at. wt.})$

Vedclass · Accepted Answer

$C_3H_7$

Vedclass · Answer

(C) To find the empirical formula,we calculate the mole ratio of the elements present:

	
		
			Element
			Moles $(	ext{mass}/	ext{at. wt.})$
			Simple Ratio
		
		
			$C = 83.70\%$
			$83.70 / 12 = 6.975$
			$6.975 / 6.975 = 1$
		
		
			$H = 16.30\%$
			$16.30 / 1 = 16.30$
			$16.30 / 6.975 \approx 2.33$
		
	


To convert the ratio to whole numbers,multiply by $3$:
$C: 1 	imes 3 = 3$
$H: 2.33 	imes 3 \approx 7$
Thus,the empirical formula is $C_3H_7$.

On analysis,a saturated hydrocarbon is found to contain $83.70\%$ carbon and $16.30\%$ hydrogen. The empirical formula will be (at. wt. of $C=12$, at. wt. of $H=1$).

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