Of the following outer electronic configurati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The maximum oxidation state of a transition element is determined by the total number of electrons in the $(n-1)d$ and $ns$ orbitals.For option $A

Vedclass · Accepted Answer

$(n-1)d^5 ns^2$

Vedclass · Answer

(A) The maximum oxidation state of a transition element is determined by the total number of electrons in the $(n-1)d$ and $ns$ orbitals.For option $A$: $(n-1)d^5 ns^2$,total electrons = $5 + 2 = 7$.For option $B$: $(n-1)d^8 ns^2$,total electrons = $8 + 2 = 10$ (but the maximum stable oxidation state is usually limited by the number of unpaired electrons and stability of the configuration).For option $C$: $(n-1)d^5 ns^1$,total electrons = $5 + 1 = 6$.For option $D$: $(n-1)d^3 ns^2$,total electrons = $3 + 2 = 5$.Among the given configurations,the configuration $(n-1)d^5 ns^2$ (e.g.,$Mn$ in $3d^5 4s^2$) allows for a maximum oxidation state of $+7$. While $d^8 s^2$ has more electrons,it does not exhibit an oxidation state of $+10$; transition metals typically show a maximum oxidation state corresponding to the sum of $ns$ and $(n-1)d$ electrons up to $Mn$ $(+7)$. Thus,$(n-1)d^5 ns^2$ is the correct choice for the highest common oxidation state.

Of the following outer electronic configurations of atoms,which one achieves the highest oxidation state?

Similar Questions

The chloride of which of the following elements will be coloured?

Which of the following will be a coloured ion?

Identify the order in which the spin-only magnetic moment (in $BM$) increases for the following four ions:
$(I) Fe^{2+}$
$(II) Ti^{2+}$
$(III) Cu^{2+}$
$(IV) V^{2+}$

Which of the following elements are not regarded as transition elements?

Among the following series of transition metal ions,the one where all metal ions have $3d^2$ electronic configuration is

Vedclass Test Series

Exam Paper Generator

Online Exam Module