Observe the following sets:LabelOrderProperty | vedclass

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(C) $(i)$ Bond angle: $SO_2$ $(119^{\circ})$ > $NH_3$ $(107.3^{\circ})$ > $H_2O$ $(104.5^{\circ})$. Thus,set $i$ is incorrect.$(ii)$ Dipole moment: $H

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$ii, iii, iv$ only

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(C) $(i)$ Bond angle: $SO_2$ $(119^{\circ})$ > $NH_3$ $(107.3^{\circ})$ > $H_2O$ $(104.5^{\circ})$. Thus,set $i$ is incorrect.$(ii)$ Dipole moment: $H_2O$ $(1.85 \ D)$ > $NH_3$ $(1.47 \ D)$ > $H_2S$ $(0.95 \ D)$. Thus,set $ii$ is correct.$(iii)$ Bond enthalpy is directly proportional to bond order. Bond orders are: $N_2$ $(3)$,$O_2$ $(2)$,$H_2$ $(1)$. Thus,$N_2 > O_2 > H_2$ is correct. Set $iii$ is correct.$(iv)$ Bond order: $NO^{+}$ $(3)$,$O_2$ $(2)$,$O_2^{2-}$ $(1)$. Thus,$NO^{+} > O_2 > O_2^{2-}$ is correct. Set $iv$ is correct.Therefore,sets $(ii), (iii),$ and $(iv)$ are correctly matched.

Observe the following sets:
Label Order Property
$i.$ $NH_3 > H_2O > SO_2$ Bond angle
$ii.$ $H_2O > NH_3 > H_2S$ Dipole moment
$iii.$ $N_2 > O_2 > H_2$ Bond enthalpy
$iv.$ $NO^{+} > O_2 > O_2^{2-}$ Bond order

Which of the above sets are correctly matched?

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Label	Order	Property
$i.$	$NH_3 > H_2O > SO_2$	Bond angle
$ii.$	$H_2O > NH_3 > H_2S$	Dipole moment
$iii.$	$N_2 > O_2 > H_2$	Bond enthalpy
$iv.$	$NO^{+} > O_2 > O_2^{2-}$	Bond order

Observe the following sets:LabelOrderProperty$i.$$NH_3 > H_2O > SO_2$Bond angle$ii.$$H_2O > NH_3 > H_2S$Dipole moment$iii.$$N_2 > O_2 > H_2$Bond enthalpy$iv.$$NO^{+} > O_2 > O_2^{2-}$Bond orderWhich of the above sets are correctly matched?