Observe the following reaction: 2 A + B longr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For the reaction $2 A + B \longrightarrow C$,the rate of reaction is given by:Rate $= -\frac{1}{2} \frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{d[C]

Vedclass · Accepted Answer

$4.4 	imes 10^{-3}$

Vedclass · Answer

(C) For the reaction $2 A + B \longrightarrow C$,the rate of reaction is given by:Rate $= -\frac{1}{2} \frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{d[C]}{dt}$Given that the rate of formation of $C$ is $\frac{d[C]}{dt} = 2.2 	imes 10^{-3} \ mol \ L^{-1} \ min^{-1}$.Equating the terms for $A$ and $C$:$-\frac{1}{2} \frac{d[A]}{dt} = \frac{d[C]}{dt}$$-\frac{d[A]}{dt} = 2 	imes \frac{d[C]}{dt}$$-\frac{d[A]}{dt} = 2 	imes (2.2 	imes 10^{-3}) = 4.4 	imes 10^{-3} \ mol \ L^{-1} \ min^{-1}$.

Observe the following reaction: $2 A + B \longrightarrow C$. The rate of formation of $C$ is $2.2 \times 10^{-3} \ mol \ L^{-1} \ min^{-1}$. What is the value of $-\frac{d[A]}{dt}$ (in $mol \ L^{-1} \ min^{-1}$)?

Similar Questions

Which of the following statements is/are incorrect?

The osmotic pressure of equimolar solutions of $BaCl_2, NaCl$ and glucose at the same temperature follows the order:

The second maturation division of the mammalian ovum occurs:

The direction of the angular velocity vector is along

$A$ coin is dropped in a lift. It takes time $t_1$ to reach the floor when the lift is stationary. It takes time $t_2$ when the lift is moving down with constant acceleration $a$. Then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module