Number of unpaired electrons in Mn^{4+} is | vedclass

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(A) The atomic number of $Mn$ is $25$. The electronic configuration of $Mn$ is $[Ar] \, 3d^5 \, 4s^2$.To form $Mn^{4+}$,we remove $4$ electrons ($2$ f

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$3$

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(A) The atomic number of $Mn$ is $25$. The electronic configuration of $Mn$ is $[Ar] \, 3d^5 \, 4s^2$.To form $Mn^{4+}$,we remove $4$ electrons ($2$ from $4s$ and $2$ from $3d$).The electronic configuration of $Mn^{4+}$ is $[Ar] \, 3d^3$.According to Hund's rule,the three electrons in the $3d$ subshell occupy separate orbitals,resulting in $3$ unpaired electrons.

List-$I$ (Element)	List-$II$ (Block)
$A$. $Cd$	$I$. $f$-block
$B$. $Eu$	$II$. $s$-block
$C$. $Se$	$III$. $d$-block
$D$. $Ba$	$IV$. $p$-block

Number of unpaired electrons in $Mn^{4+}$ is

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The correct answer is:

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