Number of stereoisomers possible for the comp | vedclass

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(C) $1$. For the complex $[CrCl_3(py)_3]$, which is of the type $[MA_3B_3]$, it exhibits geometrical isomerism with two isomers: facial $(fac)$ and me

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$2 \ & \ 3$

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(C) $1$. For the complex $[CrCl_3(py)_3]$, which is of the type $[MA_3B_3]$, it exhibits geometrical isomerism with two isomers: facial $(fac)$ and meridional $(mer)$. Neither of these is optically active. Thus, the total number of stereoisomers is $2$.$2$. For the complex $[CrCl_2(ox)_2]^{3-}$, which is of the type $[M(AA)_2B_2]$, it exhibits geometrical isomerism with two isomers: $cis$ and $trans$.$3$. The $cis$ isomer is optically active and exists as a pair of enantiomers ($d$ and $l$ forms), while the $trans$ isomer is optically inactive (achiral). Thus, the total number of stereoisomers is $3$ ($cis-d$, $cis-l$, and $trans$).$4$. Therefore, the number of stereoisomers for $[CrCl_3(py)_3]$ and $[CrCl_2(ox)_2]^{3-}$ are $2$ and $3$ respectively.

Number of stereoisomers possible for the complexes, $[CrCl_3(py)_3]$ and $[CrCl_2(ox)_2]^{3-}$ are respectively $(py = \text{pyridine}, ox = \text{oxalate})$

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