The number of neutrons in a parent nucleus X, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $\beta$ emission increases the atomic number by $1$ while the mass number remains unchanged.Let the parent nucleus be $_Z X^A$.After two successiv

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(A) $\beta$ emission increases the atomic number by $1$ while the mass number remains unchanged.Let the parent nucleus be $_Z X^A$.After two successive $\beta$ emissions,the reaction is: $_Z X^A \xrightarrow{-2\beta} _{Z+2} N^{14}$.Comparing the atomic number and mass number,we get $Z+2 = 7$,so $Z = 5$,and $A = 14$.The parent nucleus is $_5 X^{14}$.The number of neutrons in $_5 X^{14}$ is $A - Z = 14 - 5 = 9$.

The number of neutrons in a parent nucleus $X$,which gives a $_7N^{14}$ nucleus after two successive $\beta$ emissions,is:

Similar Questions

Starting from radium,the radioactive disintegration process terminates when the following is obtained:

The number of neutrons in the parent nucleus which gives $^{14}N$ on $\beta$-emission is

The nucleus of a radioactive element possesses:

$_{95}Am^{241}$ and $_{90}Th^{234}$ belong respectively to

Formation of a nucleus from its nucleons is accompanied by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module