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(B) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - N)$,where $V$ is the number of

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$2, 1, 2$ and $0$

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(B) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - N)$,where $V$ is the number of valence electrons of the central atom and $N$ is the number of bonding electrons (or atoms attached).$1$. For $SCl_2$: Sulfur $(S)$ has $6$ valence electrons. It forms $2$ bonds with $Cl$ atoms. Lone pairs = $\frac{1}{2} (6 - 2) = 2$.$2$. For $O_3$: The central Oxygen atom has $6$ valence electrons. It forms $2$ bonds with one oxygen atom and $1$ coordinate bond with another. The central atom has $1$ lone pair.$3$. For $ClF_3$: Chlorine $(Cl)$ has $7$ valence electrons. It forms $3$ bonds with $F$ atoms. Lone pairs = $\frac{1}{2} (7 - 3) = 2$.$4$. For $SF_6$: Sulfur $(S)$ has $6$ valence electrons. It forms $6$ bonds with $F$ atoms. Lone pairs = $\frac{1}{2} (6 - 6) = 0$.Thus,the number of lone pairs are $2, 1, 2$ and $0$ respectively. The correct option is $B$.

List-$I$	List-$II$
$(a)$ $PCl_{5}$	$(i)$ Square pyramidal
$(b)$ $SF_{6}$	$(ii)$ Trigonal planar
$(c)$ $BrF_{5}$	$(iii)$ Octahedral
$(d)$ $BF_{3}$	$(iv)$ Trigonal bipyramidal

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $NH_3$	$I$. Square pyramid
$B$. $BrF_5$	$II$. Tetrahedral
$C$. $PCl_5$	$III$. Trigonal pyramidal
$D$. $CH_4$	$IV$. Trigonal bipyramidal

The number of lone pairs of electrons on the central atom of $SCl_2$,$O_3$,$ClF_3$,and $SF_6$,respectively,are:

Similar Questions

The geometry of $ClO_3^-$ according to valence shell electron pair repulsion $(VSEPR)$ theory will be

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$(a)$ $PCl_{5}$ $(i)$ Square pyramidal

$(b)$ $SF_{6}$ $(ii)$ Trigonal planar

$(c)$ $BrF_{5}$ $(iii)$ Octahedral

$(d)$ $BF_{3}$ $(iv)$ Trigonal bipyramidal

Choose the correct answer from the options given below.

The geometrical arrangement of orbitals and shape of $I_3^-$ are respectively

Match List-$I$ with List-$II$:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $NH_3$ $I$. Square pyramid

$B$. $BrF_5$ $II$. Tetrahedral

$C$. $PCl_5$ $III$. Trigonal pyramidal

$D$. $CH_4$ $IV$. Trigonal bipyramidal

Choose the correct answer from the options below:

Which of the following is not correctly matched?

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