Number of letters skipped in between adjacent | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To find the correct alternative,we check the number of letters skipped between consecutive letters in each option based on the English alphabet po

Vedclass · Accepted Answer

$UROLIF$

Vedclass · Answer

(C) To find the correct alternative,we check the number of letters skipped between consecutive letters in each option based on the English alphabet positions.$A) SPMLI$: $S(19) \rightarrow P(16)$ (skipped $R, Q$ - $2$ letters),$P(16) \rightarrow M(13)$ (skipped $O, N$ - $2$ letters),$M(13) \rightarrow L(12)$ (skipped $0$ letters). This does not follow the rule.$B) TSPNKH$: $T(20) \rightarrow S(19)$ (skipped $0$ letters). This does not follow the rule.$C) UROLIF$: $U(21) \rightarrow R(18)$ (skipped $T, S$ - $2$ letters),$R(18) \rightarrow O(15)$ (skipped $Q, P$ - $2$ letters),$O(15) \rightarrow L(12)$ (skipped $N, M$ - $2$ letters),$L(12) \rightarrow I(9)$ (skipped $K, J$ - $2$ letters),$I(9) \rightarrow F(6)$ (skipped $H, G$ - $2$ letters). This follows the rule of skipping two letters between every adjacent letter.$D) WTQNKJ$: $W(23) \rightarrow T(20)$ (skipped $V, U$ - $2$ letters),$T(20) \rightarrow Q(17)$ (skipped $S, R$ - $2$ letters),$Q(17) \rightarrow N(14)$ (skipped $P, O$ - $2$ letters),$N(14) \rightarrow K(11)$ (skipped $M, L$ - $2$ letters),$K(11) \rightarrow J(10)$ (skipped $0$ letters). This does not follow the rule.Therefore,option $C$ is the correct answer.

Number of letters skipped in between adjacent letters in the series is two. Which one of the following alternatives observes this rule?

Similar Questions

Study the letter series given below and answer the question that follows:
$H, D, Y, S, M, W, N, B, Q, P, O, C, R, T, B, L, Z, V, E, G, U, F$
Which letter has the same neighbours as in the alphabetical order,although they have changed places?

$A$ group of letters is given which are numbered $1, 2, 3, 4, 5$. Below are given four alternatives containing combinations of these numbers. Select the combination of numbers so that the letters arranged accordingly form a meaningful word.
$R, P, E, D, I$
$1, 2, 3, 4, 5$

Find which one word cannot be made from the letters of the given word: $KALEIDOSCOPE$.

How many pairs of letters are there in the word $DELUSION$ which have as many letters between them in the word as there are in the English alphabet?

Vedclass Test Series

Exam Paper Generator

Online Exam Module