Number of letters skipped in between adjacent | vedclass

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Question

(A) To find the series that follows the rule of skipping $1^{2}, 2^{2}, 3^{2}$ letters between adjacent letters,let us analyze the options:For option

Vedclass · Accepted Answer

$CEJT$

Vedclass · Answer

(A) To find the series that follows the rule of skipping $1^{2}, 2^{2}, 3^{2}$ letters between adjacent letters,let us analyze the options:For option $C$ $(EGLP)$:$1$. Between $E$ and $G$: $F$ is skipped. Number of letters skipped = $1 = 1^{2}$.$2$. Between $G$ and $L$: $H, I, J, K$ are skipped. Number of letters skipped = $4 = 2^{2}$.$3$. Between $L$ and $P$: $M, N, O$ are skipped. Wait,$L$ is $12$,$P$ is $16$. Letters between them are $M, N, O, P$. Actually,the letters between $L$ and $P$ are $M, N, O$. The number of letters is $3$. This does not fit $3^{2} = 9$.Let us re-evaluate $EGLP$:$E(5), G(7), L(12), P(16)$.$G-E-1 = 7-5-1 = 1 = 1^{2}$.$L-G-1 = 12-7-1 = 4 = 2^{2}$.$P-L-1 = 16-12-1 = 3$. Incorrect.Let us check $CEJT$:$C(3), E(5), J(10), T(20)$.$E-C-1 = 5-3-1 = 1 = 1^{2}$.$J-E-1 = 10-5-1 = 4 = 2^{2}$.$T-J-1 = 20-10-1 = 9 = 3^{2}$.This matches the pattern $1^{2}, 2^{2}, 3^{2}$.Therefore,the correct option is $A$.

Number of letters skipped in between adjacent letters in the series is in the order of $1^{2}, 2^{2}, 3^{2}$. Which of the following series observes the rule given above?

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