Number of electrons in the valence orbit of n | vedclass

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(B) The electronic configuration of nitrogen $(Z=7)$ is $1s^2, 2s^2, 2p^3$. Nitrogen has $5$ valence electrons. In an ammonia $(NH_3)$ molecule,nitrog

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$8$

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(B) The electronic configuration of nitrogen $(Z=7)$ is $1s^2, 2s^2, 2p^3$. Nitrogen has $5$ valence electrons. In an ammonia $(NH_3)$ molecule,nitrogen shares $3$ of its valence electrons with $3$ hydrogen atoms to form $3$ covalent bonds. After sharing,nitrogen gains $3$ electrons from the hydrogen atoms,completing its octet. Therefore,the total number of electrons in the valence shell of nitrogen in $NH_3$ is $5 + 3 = 8$.

Number of electrons in the valence orbit of nitrogen in an ammonia molecule are

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